21-09-2016, 02:40 PM
I don't understand where '1/2 Deceleration time' or '1/2 Acceleration time' equates to 33.3 m/s?
By adding the above time to non stopping headway we get stopping headway.
3 aspect stopping headway = 3 aspect non stopping headway + ½ Deceleration time + Station dwell time + ½ Acceleration time
3 aspect stopping headway = 112+33.33+30+33.33
Can anyone clarify, as I was working it out to be: 112+66.6+30+66.6
By adding the above time to non stopping headway we get stopping headway.
3 aspect stopping headway = 3 aspect non stopping headway + ½ Deceleration time + Station dwell time + ½ Acceleration time
3 aspect stopping headway = 112+33.33+30+33.33
Can anyone clarify, as I was working it out to be: 112+66.6+30+66.6